Question
Train 'X' is 500 meters long and it crosses a pole in 25
seconds and it also passes Train 'Y', which is moving in the opposite direction, in 20 seconds. If Train 'Y' is 2 times as long as Train 'X', then find the distance travelled by Train Y in 30 minutes.Solution
Speed of Train 'X' = 500 ÷ 25 = 20 m/s Length of Train 'Y' = 2 × 500 = 1000 meters Combined length of Train 'X' and 'Y' = 500 + 1000 = 1500 meters Relative speed of train 'X' w.r.t train 'Y' when travelling towards each other = 1500 ÷ 20 = 75 m/s So, speed of Train 'Y' = 75 - 20 = 55 m/s Therefore, distance covered by Train Y in 30 minutes = 55 × 30 × 60 = 99,000 meters = 99 km
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