Question
A train 180 m long passes a man standing on a platform
in 12 seconds and passes the platform completely in 30 seconds. Find the speed of the train in km/h and the length of the platform.Solution
ATQ, Speed of train: Speed = distance / time (when passing the man) = 180 / 12 = 15 m/s Convert to km/h: 15 × (18/5) = 54 km/h When passing the platform, distance covered = length of train + length of platform Let platform length = L. Speed = 15 m/s, time = 30 s ⇒ 15 × 30 = 180 + L 450 = 180 + L ⇒ L = 270 m Speed = 54 km/h, platform length = 270 m.
(√780 + 111.98) ÷ 6.95 + 39.95% of 179.98 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1120.04 – 450.18 + 319.98 ÷ 8.06 = ?
660 × ? + 495.85 - 60% of 9650 = 37.5% of 7200
(462.23 × 127.84 ÷ 153.88) ÷ √(31.98 × 7.92) = ? ÷ 15.15
(9.013 – 15.04) = ? + 9.98% of 5399.98
17.06 2 + √36.08 – (4.04/2.99) × 3.02 × 4.92 = ? × 4.99
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
?% of 1200.22 + 319.82 = 3.99 × 295.64
( 1728)1/3  × 10.11 × 3.97 ÷ 8.32 = ? + 15.022
