Question
A train can cross a pole in 6 seconds while it can cross
a 240 metres long platform in 18 seconds. Find the time (in hours) taken by the train to cover a distance of 540 km if the train increased its speed by 50%.Solution
Let speed of train is ‘x’ m/s while length of the train is ‘l’ metres.
So, l = 6x
And, l + 240 = 18x
⇒ 6x + 240 = 18x
⇒ 12x = 240
⇒ x = 20
Speed = 20 × 18/5 = 72 km/h
Increased speed = 1.5 × 72 = 108 km/h
Time = 540 / 108 = 5 hours
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
[(2/3 of 599.77) + (39.69% of 450.14)] ÷ [(5/8 of 399.79) - √120.91] = ?
(?)2 + 8.113 = 28.92 – 73.03
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
(71.78 × 59.88 ÷ 17.92 ÷ 120.22 × 161.72)% of 32 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
What approximate value should come in the place of question mark in the following questions?
(359.92 ÷ 24.02) + (230.04 ÷ 5) = ?% of 210.0 - 86...
