Question
Train A when travelling with a speed of 90 km/h crosses a
pole in 10 seconds. Find the time taken by the train A to cross another train B of length 20% more than that of train A which is coming from the opposite direction with a speed of 54 km/h.Solution
Speed of train A = 90 × 5/18 = 25 m/s
Length of train A = 25 × 10 = 250 metres
Length of train B = 1.2 × 250 = 300 metres
Speed of train B = 54 × 5/18 = 15 m/s
Relative speed = 25 + 15 = 40 m/s (opposite direction)
Total distance = 250 + 300 = 550 metres
Desired time = 550/40 = 13.75 seconds
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