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    Question

    Train A when travelling with a speed of 90 km/h crosses a

    pole in 10 seconds. Find the time taken by the train A to cross another train B of length 20% more than that of train A which is coming from the opposite direction with a speed of 54 km/h.
    A 12.5 seconds Correct Answer Incorrect Answer
    B 13.75 seconds Correct Answer Incorrect Answer
    C 14.2 seconds Correct Answer Incorrect Answer
    D 15 seconds Correct Answer Incorrect Answer
    E 16.5 seconds Correct Answer Incorrect Answer

    Solution

    Speed of train A = 90 × 5/18 = 25 m/s
    Length of train A = 25 × 10 = 250 metres
    Length of train B = 1.2 × 250 = 300 metres
    Speed of train B = 54 × 5/18 = 15 m/s
    Relative speed = 25 + 15 = 40 m/s (opposite direction)
    Total distance = 250 + 300 = 550 metres
    Desired time = 550/40 = 13.75 seconds

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