Question
Two trains ‘T8’ and ‘U8’ of lengths 600 metres and
300 metres respectively are travelling towards each other. Ratio of speed of ‘T8’ to ‘U8’ is 3:2. If the trains take 36 seconds to cross each other from the time they meet, then find the average of speeds (in km/h) of trains ‘T8’ and ‘U8’.Solution
Let the speed of ‘T8’ and ‘U8’ be ‘3y’ and ‘2y’ m/s respectively.
Relative speed = 3y + 2y = 5y m/s
ATQ,
5y × 36 = 600 + 300
⇒ 180y = 900
⇒ y = 5
Therefore, required average = (3y + 2y) ÷ 2 = 2.5y
= 2.5 × 5 = 12.5 m/s = 12.5 × (18/5) = 45 km/h
Statements: N # L, L @A, A % I, I & E
Conclusions :
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...Statement: C < P > T = E < R; G > R > A < D
Conclusions:
I. T < G
II. G ≥ P
III. T > A
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Statement: T > B = P `>=` C ; B `>=` J > F; O `<=` J `<=` C
Conclusions: I. J < T II. T > F
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Statements: I ≤ J = K < L < M, G ≥ H = I = T
Conclusions:
I. J > G
II. M = H
III. M > H
...In the question, assuming the given statements to be true, find which of the following conclusion(s) among the three conclusions is/are true and then g...
Statements: C ≥ E > M ≤ Z < B; G ≥ Z > K
Conclusions: I. C > K II. G ≥ B �...
Statements : C © S * R, U % R $ Z
Conclusions :
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Statements: F % W, W © R, R @ M, M $ D
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