Question
A train crosses a pole and a platform of length 672
metres in 14 seconds and 30 seconds, respectively. Find the length of train.Solution
Let the speed of train be 'v' m/s.
Length of train = '14v' metres
So, (14v + 672) ÷ 30 = 'v'
Or, 14v + 672 = 30v
Or, 16v = 672
So, 'v' = 42
Therefore, length of the train = 14 × 42 = 588 metres
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
[√ (121.23) ÷ √ (12100.04)] × √ 80.95 = 3/10 + ? ÷ 4
...40.93√? + √6625 + √6920 + √? = 205.7542`xx` 7.654
13.232 + 19.98% of 549.99 = ? × 8.99
(29.892 × √290) + 32.98 × 6.91 = ?
(`sqrt(224.95)` `xx` `sqrt(440.89)` ) + (`sqrt(783.82)` `xx` `sqrt(440.87)` ) = ? + 150.03% of 120.33 - 139.86% of 1249.88
...8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
