Question
A train crosses a pole and a platform of length 504
metres in 9 seconds and 21 seconds, respectively. Find the length of train.Solution
Let the speed of train be 'v' m/s.
Length of train = '9v' metres
So, (9v + 504) á 21 = 'v'
Or, 9v + 504 = 21v
Or, 12v = 504
So, 'v' = 42
Therefore, length of the train = 9 Ă 42 = 378 metres
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