Question
Train 'A' having a speed of 10 m/s can cross a man in 15
seconds. The length of train 'B' is 150 metres more than the length of 'A'. If the speed of 'B' is 50 m/sec and both trains are travelling towards each other, then find the time taken by them to cross each other.Solution
Length of train 'A' = 10 × 15 = 150 metres
Length of train 'B' = 150 + 150 = 300 metres
Relative speed = 10 + 50 = 60 m/sec
Required time = (150 + 300) ÷ 60 = 450 ÷ 60 = 7.5 seconds
Rs. 2500 is invested in scheme ‘A’ for a year at simple interest of 25% p.a. The interest received from scheme ‘A’ is reinvested for 2 years in ...
- A businessman took a loan at 25% p.a. simple interest. After 40 months, he repaid Rs. 12,500 to clear the loan. Find the principal amount borrowed.
A certain amount is split equally between two investment plans. One offers simple interest and the other compound interest, both at the same annual rate...
An amount of Rs. x is invested in simple interest at 5% per annum for 4 years. If another amount of Rs. (x + 250) is also invested at the same rate for...
- Rs. 3,000 becomes Rs. 4,200 in 10 years at simple interest of r% p.a. If Rs. 6,000 is invested at 0.5r% p.a. for 6 years, what will be the interest amount?
Maya invested Rs. 5000 in scheme 'E' for 2 years and Rs. 6000 in scheme 'F' for 5 years. Both schemes offer a simple interest rate of 10% per annum. Fin...
A sum of Rs. 6120 is invested at simple interest for 2 years. If the rate interest for first year is 15% p.a. while 25% p.a. for second year, then find ...
The simple interest on a sum of money for 4 years at 9% per annum is Rs 2160. Find the principal.
The simple interest on a sum of Rs. (6400 + x) invested for 3 years is Rs. 4,800. If the interest rate is 12.5% per annum, find the value of x.
Deepa placed Rs. 3500 at R% p.a. simple interest for 6 years and Rs. 1500 at (R + 4)% p.a. simple interest for 6 years. If her total interest is Rs. 45...