Question
A train moving at 72 km/h takes 20 seconds to pass a
pole. Find the time required for the train to cross a platform that is 0.6 times the length of the train.Solution
ATQ, Length of the train = (72 × (5/18) × 20) = 400 metres Length of the platform = (400 × 0.6) = 240 metres Time taken by train to cross the platform = [(400 + 240) / (72 × (5/18))]= (640 / 20) = 32 seconds
25.04 × 22.03 + 383.92 ÷ ? + 23.78% of 1499.98 = 926.08Â
(289.89 + 59.98) X 2.25 = ? X 49.66
What approximate value will replace the question mark (?) in the following?
14.98...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.98% of 399.99) - 6.998 = √?
(23.95)2 – (25.006)2 + (8.0099)2 – (7.07)2 = ? - (14.990)2
194.95 + 3.98 × 64.99 - ? = (10.99 + 9.02)2
25.11% of 239.99 + √143.97 ÷ 12.02 = ?
45.45 × 11.67 + 14399.88 ÷ 8.01 + 124.79 = ?
(278% of 695) ÷ 543 =?