Question
Aruna is aboard train A, which is moving at a speed of
50 km/h. Another train, train B, travels in the opposite direction at 58 km/h and has a length three times that of train A. When train B passes Aruna in just 15 seconds, we are asked to determine the length of train A. (in metres).Solution
Relative speed = 50 + 58 = 108 km/h = 108 Γ 5/18 = 30 m/s Let length of train A be βxβ meters So, 3x = 30 Γ 15 Or, 3x = 450 Or, x = 150 metres
10.10% of 999.99 + 14.14 Γ 21.21 - 250.25 = ?
56.05 2 β 24.24 2 + (63.98) 3/2 β 32.28% of 1500 = ? 2 + 113.03 Γ 5.09Β
What will be the approximate value of the following questions.
125.9% Γ· 9.05 x 99.98 = ? - 69.97 Γ β324.02 Γ· 5.98
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(98.03 + 186.98) Γ· 19.211 = 89.9 β 20.23% of ?
11.232 + 29.98% of 599.99 = ? Γ 6.99
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
(899.78 Γ· 15.11) Γ (β143.94 + 10.02) β 230...
(36.35 Γ 14.89) Γ· 8.78 = ? β 59.98