Question
The time taken by train B to cross a platform of 120
metres is 3 sec less than the time taken by train A to cross the same platform. The sum of length of train A and B is 600 metres. The ratio of speeds of trains A and B is 3:2 respectively. Find the speed of train B.Solution
ATQ,
Let the length of train A = LA and length of train B = LB respectively, Speed of train A = 3x, Speed of train B = 2x.
From the problem:
Substitute LB = 600 − LA into the equation and simplify: 2LA − 3LB − 120 = 18x,
Solve to get LA = 18x/5 + 384. Use this relation to calculate 'x' or LA with additional constraints or assumptions about 'x' is not mention Hence, it Can't be determined
2 4 5 19 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If 204 196 223 x 284
Then, what is the average of the numbers of the above series?
...8 24 12 ? 18 54
3 ? 7 16 71 346
...104 106 110 113 ? 126
12, 18, 28, 42, 52, ?
18 29 51 84 128 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?