Question
A train moves at 90 km/h to
arrive at its station on time. If it moves at 100 km/h, it will arrive 15 minutes earlier. Find the time taken by the train to travel four times the distance at 120 km/h.Solution
ATQ, Let the usual time taken by the train be 'T' hours. Using, distance = speed × time We have, 'D' = 90T ----------- (I) And, 'D' = 100 × {T - (15/60)} -------- (II) From equation (I) and (II), We have, 90T = 100 × {T - (15/60)} Or, 90T = 100T - 100 × (15/60) Or, 10T = 25 Or, 'T' = 2.5 On putting the value of 'T' = 2.5 in equation (I), We have 'D' = 90 × 2.5 = 225 km So, the required time = (4 × 225) ÷ 120 = (900/120) = 7.5 hours
In an LLP out of the designated partners:
Imputation of truth made for public good_________________.
Where a banking company appropriates any sum or sums from the reserve fund or the share premium account, it shall, within _______________, report the fa...
Under the Insurance Act, 1938 , which of the following is the minimum paid-up capital requirement for a company to carry out life or general insurance b...
The authority to alter the boundaries of states in India lies with
A is accused of the murder of B by beating him. Whatever was said or done by A or B or by the by-standers at the beating, or so shortly before or after ...
What does the principle of Caveat Emptor imply in the context of a contract of sale according to Section 16 of the Sale of Goods Act?
For how long can the Registrar reserve a name for a limited liability partnership after satisfying the prescribed conditions and payment of the fee?
No person shall be appointed by the State Government as the Public Prosecutor or Additional Public Prosecutor for the district unless his name appears i...
The superintendence of the Delhi Special Police Establishment in so far as it relates to investigation of offences alleged to have been committed under ...
Relevant for Exams:
