Question
Train X, traveling at a speed of 36 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 72 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 5:4, and train X crosses a pole in 40 seconds, find the value of (t + 11).Solution
Length of train X = 40 × 36 × (5/18) = 400 m Length of train Y = (400/5) × 4 = 320 m => t = (400 + 320)/[(36 + 72) ×(5/18)] = 24 sec Required value = (t + 11) = 24 + 11 = 35
More Trains Questions
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
570.11 ÷ 18.98 × 5.14 – 123.9 = √?Â
5466.97 - 3245.01 + 1122.99 = ? + 2309.99
25.09 × (√15 + 19.83) = ? of 19.87 ÷ 4.03Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√? + √626 × 13.998 - 6.02 × 2.97 = 345.995Â
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...√3601 × √(224) ÷ √102 = ?
`sqrt(7.987 X 24.790 +199.991)`
What will come in place of the question mark (?) in the following series?
2, 4, 12, 60, 420, ?
