Question
Train X, traveling at a speed of 36 km/hr, crosses
another train Y, which is moving in the opposite direction at a speed of 72 km/hr, in 't' seconds. If the ratio of the lengths of train X and train Y is 5:4, and train X crosses a pole in 40 seconds, find the value of (t + 11).Solution
Length of train X = 40 × 36 × (5/18) = 400 m Length of train Y = (400/5) × 4 = 320 m => t = (400 + 320)/[(36 + 72) ×(5/18)] = 24 sec Required value = (t + 11) = 24 + 11 = 35
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