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Length of the train = 32 × 10 = 320 metres Let the length of the platform be ‘p’ metres ATQ; p + 320 = 32 × 50 Or, p = 1600 – 320 Or, p = 1280
15% of 1800 + 22 = ?
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
[(120)2 ÷24 ×25] ÷ 250 =?
84367 + 65441 + 32645 – 21145 – 10769 = ?
(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²
2 X 25 + (30% of 80) ÷ (10% of 120) = ?
(630 ÷ 35) × 2 + 144 = ? × 2
1120 / √x = 80 Then x = ?
(49 x ?) / 3.5 + 389 = 627
√256 * 3 – 15% of 300 + ? = 150% of 160