Question
Two trains started from stations βAβ and βBβ at
same time and started travelling towards each other at speeds of 65 km/hr and 55 km/hr, respectively. At the time of their meeting, the faster train has travelled 120 km more than the slower train. Find the distance between the stations βA and βBβ.Solution
Let the distance travelled by slower train be βxβ km So, distance travelled by faster train = βx + 120β km ATQ, (x/55) = {(x + 120)/65} Or, 65x = 55x + 6600 Or, 10x = 6600 So, x = 660 Total distance between station βAβ and station βBβ = (660 + 660 + 120) = 1440 km
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