Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 120’ km ATQ, (x/55) = {(x + 120)/65} Or, 65x = 55x + 6600 Or, 10x = 6600 So, x = 660 Total distance between station ‘A’ and station ‘B’ = (660 + 660 + 120) = 1440 km
Statement: M < N ≤ O = P, Q ≥ O ≤ R ≤ Z
Conclusion: I. Q > M II. Z > M
...Statements: S ≥ W = R > I < M > F > P ≤ X
Conclusion I: S > R
II: P < M
Statements :
A > B > C
Y > B
D > C > Z
Conclusions :
I. Z > D
II. Y > A
III. B > Z
...Statements:
Only a few Bottle is Cap.
No Cap is Surface.
No Surface is Structure.
Conclusion:
Statement: L = C; E ≥ M ≥ U ≥ C
Conclusion:
I. E > L
II. E = L
Answer the following question based on the direction given below.
If 'A#B' means 'A is equal to B'
Statements:
B > C = Z ≥ Q ≥ O; X < C ≤ D < O
Conclusions:
I. O > X
II. B > O
Statement: M ≤ W, W < F, F = V, V ≥ C.
Conclusion: I. C > W II. M ≥ C
Statements: U > G = L > V < K ≤ C > S < N
Conclusion I: U ≥ V
II: C > V