Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 65 km/hr and 55 km/hr, respectively. At the time of their meeting, the faster train has travelled 120 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 120’ km ATQ, (x/55) = {(x + 120)/65} Or, 65x = 55x + 6600 Or, 10x = 6600 So, x = 660 Total distance between station ‘A’ and station ‘B’ = (660 + 660 + 120) = 1440 km
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