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Start learning 50% faster. Sign in nowLet the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 120’ km ATQ, (x/55) = {(x + 120)/65} Or, 65x = 55x + 6600 Or, 10x = 6600 So, x = 660 Total distance between station ‘A’ and station ‘B’ = (660 + 660 + 120) = 1440 km
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