Question
Ratio of the lengths of two trains βXβ and βYβ
is 3:4 respectively and the ratio of time taken by them to cross a pole is 1:2 respectively. If speed of train βXβ is 108 km/h, then find the speed of train βYβ.Solution
Speed of Train Y = 108 Γ (4/2) Γ (1/3) => 108 Γ 2/3 = 72 km/h
Solve the following equation.
143 + 14.3 + 1.43 + 0.143 + 0.0143 =?
What will come in the place of question mark (?) in the given expression?
? = (266 Γ 276) Γ· (114 Γ 161) Γ 17
8 Γ 9 + ? β 6 Γ 11 = 12 Γ 8
?3 - 25 Γ 11 = 30 - 15 Γ 12
18 Γ 15 + 86 β 58 =? + 38
Β
What will come in the place of question mark (?) in the given expression?
(50 Γ 6 Γ· 12) Γ 9 = ?
β529 * 5 β 15% of 220 + ? = 120% of 160
β(82Β Γ 7Β Γ 52 - 175) = ?
18 + 28 ÷ 4 - 14 = ? - 35
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