Question
1440 metres long train crosses a man who is moving in
the same direction with a certain speed in 30 seconds. If the same train can cross a pole in 24 seconds with the same speed, then find the speed of the man.Solution
Let the speed of the man be ‘x’ m/sec. Speed of train = 1440/24 = 60 m/sec Relative speed of the train = (60 – x) m/sec According to the question, => (60 – x) = 1440/30 => x = 60 – 48 => x = 12 Therefore the speed of the man = 12 m/sec
More Trains Questions
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
28.95% of 924.78 + 1955% of 38.99 = ?
? + 151.99 – 100.01 = 23.01 × 4.98
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
233.98 + 73 × √35.95 - ? = 275.94 ÷ 3.99
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
37.06% of 783.45 + 2125% of 51.89 = ?
2 (1/4)% of 7999.58 + {49.06% of 898.87} + √143.14 – 19.99% of 1499.63 - (52 - 41) = ?
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?
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