Question
1440 metres long train crosses a man who is moving in the same direction with a certain speed in 30 seconds. If the same train can cross a pole in 24 seconds with the same speed, then find the speed of the man.
Solution
Let the speed of the man be ‘x’ m/sec. Speed of train = 1440/24 = 60 m/sec Relative speed of the train = (60 – x) m/sec According to the question, => (60 – x) = 1440/30 => x = 60 – 48 => x = 12 Therefore the speed of the man = 12 m/sec
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