Question
A man running at the speed of 5 kmph was over taken by
the train moving with the speed of 41 kmph in 20 seconds. Find the length of train.Solution
According to the question, Let length of train be βxβ m. => (Speed of train β Speed of man) = Length of train/Time => (41 - 5)Γ (5/18) = x/20 => 10 = x/20 => x = 200 Length of train is 200 meter.
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (β 484 β β 256) = ?
(13)2Β - 3127 Γ· 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 Γ· 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 Γ 5 - {272 + 162 - 422}
(15 Γ 225) Γ· (45 Γ 5) + 480 = ? + 25% of 1240
β [? x 11 + (β 1296)] = 16
11 Γ 25 + 12 Γ 15 + 14 Γ 20 + 15 = ?