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      Question

      A 280 m long train crosses a platform twice its length

      in 2 min. Find the speed of the train. TYPE 2
      A 8 m/s Correct Answer Incorrect Answer
      B 5 m/s Correct Answer Incorrect Answer
      C 11 m/s Correct Answer Incorrect Answer
      D 7 m/s Correct Answer Incorrect Answer
      E 9 m/s Correct Answer Incorrect Answer

      Solution

      Speed of train = (Length of train + Length of Platform)/Required time Length of train = 280 m Crossing time of platform = 2 × 60 = 120 sec Length of platform = 280 × 2 = 560 m Let the speed of train be x. Speed of train = (280 + 560)/120 ⇒  x = 840/120 = 7 m/s

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