Question
Train A running at a speed of 31 km/hr crosses train B
in 20 seconds. Find the speed of train B (in km/hr), if the sum of the length of train A and B is 250 meters and both trains running in the opposite direction.Solution
Let speed of train B be ‘x’ km/hr. According to question, => 20(31 + x) × (5/18) = 250 => 620 + 20x = 900 => 20x = 280 => x = 14 km/hr
More Trains Questions
54.97% of 620.08 + 16.13 × 11.11 – 829.91 ÷ 5 = ?
123% of 3825 +2745 =11800 - ?
...? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
(699.88% of 32) + (80.44% of 400.23) = ? + (11.67)2
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
? = 200.24 + 1077.97 – 14.992
(8.013 – 25.04) = ? + 11.98% of 2399.98
7/12 of 539.98 – 23.98 × 9.03 + 77.89 = ?
Relevant for Exams:
