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Let distance travelled by train ‘A’ at the time of meet = ‘x’ km So, distance travelled by train ‘B’ at the time of meet = ‘x + 128’ km According to question; x + x + 128 = 200 => 2x = 72 => x = 36 Distance travelled by train ‘A’ in 18 hours = 36 km Speed of train ‘A’ = 36/18 = 2 km/h Distance travelled by train ‘A’ in 10 hours = 10 × 2 = 20 km
The number of pixels displayed on a screen is known as
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A set of programs that enables your computer’s hardware devices and application software to work together is calledÂ
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The files which are deleted from hard disk goes to
_______ operation relates to a set of computers connected to a LAN.
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