Question
Two trains ‘A’ and ‘B’ started from station
‘P’ and ‘Q’ towards station ‘Q’ and ‘P’ respectively at the same time. When they met after 18 hours, train ‘B’ has travelled 128 km more than train ‘A’. Find the distance travelled by train ‘A’ in 10 hours if distance between both stations is 200 km.Solution
Let distance travelled by train ‘A’ at the time of meet = ‘x’ km So, distance travelled by train ‘B’ at the time of meet = ‘x + 128’ km According to question; x + x + 128 = 200 => 2x = 72 => x = 36 Distance travelled by train ‘A’ in 18 hours = 36 km Speed of train ‘A’ = 36/18 = 2 km/h Distance travelled by train ‘A’ in 10 hours = 10 × 2 = 20 km
? = (597.98 ÷ (6.97 2.01 – 3.1)) × 12.9
1153, 1206, ?, 1326, 1393, 1464
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