Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 15 hours, train βBβ has travelled 150 km more than train βAβ. Find the distance travelled by train βAβ in 10 hours if distance between both stations is 555 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 150β km According to question; x + x + 150 = 555 => 2x = 405 => x = 202.5 Distance travelled by train βAβ in 15 hours = 202.5 km Speed of train βAβ = 202.5/15 = 13.5 km/h Distance travelled by train βAβ in 10 hours = 10 Γ 13.5 = 135 km
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