Question
Train βAβ running with a speed of 108 km/hr can
cross a standing goods train of 4 times its length in 30 seconds. Find the time taken by 300 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 30 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 108 Γ (5/18) = 30 m/s According to the question, 4x + x = 30 Γ 30 => 5x = 900 => x = 180 Therefore, time taken by train βBβ to cross train βAβ = {(180 + 300)/(30 + 30)} = 8 seconds
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