Question
Train βAβ running with a speed of 63 km/hr can cross
a standing goods train of 4 times its length in 24 seconds. Find the time taken by 150 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 15 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 63 Γ (5/18) = 17.5 m/s According to the question, 4x + x = 17.5 Γ 24 => 5x = 420 => x = 84 Therefore, time taken by train βBβ to cross train βAβ = {(84 + 150)/(24 + 15)} = 6 seconds
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