Question
Train ‘A’ running with a speed of 19.8 km/hr can
cross a standing goods train of 4 times its length in 40 seconds. Find the time taken by 250 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 9 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 19.8 × (5/18) = 5.5 m/s According to the question, 4x + x = 5.5 × 40 => 5x = 220 => x = 44 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(44 + 250)/(5.5 + 9)} = 20.2 seconds
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