Question
Train βAβ running with a speed of 225 km/hr can
cross a standing goods train of 4 times its length in 30 seconds. Find the time taken by 225 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 10 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 225 Γ (5/18) = 62.5 m/s According to the question, 4x + x = 62.5 Γ 30 => 5x = 1875 => x = 375 Therefore, time taken by train βBβ to cross train βAβ = {(375 + 225)/(30 + 10)} = 15 seconds
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