Question
Train ‘A’ running with a speed of 225 km/hr can
cross a standing goods train of 4 times its length in 30 seconds. Find the time taken by 225 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 10 m/s, to cross train ‘A’.Solution
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 225 × (5/18) = 62.5 m/s According to the question, 4x + x = 62.5 × 30 => 5x = 1875 => x = 375 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(375 + 225)/(30 + 10)} = 15 seconds
More Trains Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
