Question
Train βAβ running with a speed of 108 km/hr can
cross a standing goods train of 4 times its length in 20 seconds. Find the time taken by 200 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 12 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 108 Γ (5/18) = 30 m/s According to the question, 4x + x = 30 Γ 20 => 5x = 600 => x = 120 Therefore, time taken by train βBβ to cross train βAβ = {(120 + 200)/(20 + 12)} = 10 seconds
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