Get Started with ixamBee
Start learning 50% faster. Sign in now
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 36 × (5/18) = 10 m/s According to the question, 4x + x = 10 × 30 => 5x = 300 => x = 60 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(60 + 285)/(30 + 39)} = 5 seconds
Statement: T > B = P ≥ C ; B ≥ J > F; O≤ J ≤ C