Question
A train started from station P and preceded towards
station Q at a speed of 80 km/h. 45 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 420 km, at what distance from station P will the trains meet?Solution
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 80 x 45/60 km Distance travelled by train started from station Q = (80 + 100) x t km Total distance between station P and Q = 420 km Now, 80 x (45/60) + (80 + 100) x t = 420 ⇒ 60 + 180t = 420 ⇒ 180t = 420 – 60 = 360 ⇒ t = 360/180 = 2 hours Distance travelled by train starting from station P at all meeting point = 60 + 80 x 2 = 220 km
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
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