Question
Two cars start from a place with a speed of 45 km/hr at
an interval of 10 minutes. What is the speed of a man coming from the opposite direction towards the place if he meets the cars at an interval of 9 minutes?Solution
Distance covered in 10 minutes at 45 km/hr = 45 x (10/60) Distance covered in 9 minutes at (45 + x) km/hr = (9/60) x (45 + x) Now, Distance covered in 10 minutes at 45 km/hr = Distance covered in 9 minutes at (45 + x) km/hr ⇒ 45 x (10/60) = (9/60) x (45 + x) ⇒ 45 x 10 = 405 + 9x ⇒ 450 = 405 + 9x ⇒ 9x = 450 - 405 = 45 ⇒ x = 5 km/hr
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
What approximate value should come in the place of question mark in the following questions?
25.02% of 460.02 + ?% of 300.02 = 295.21
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(2520.33 ÷ 41.67) × (√168.88 + √80.78) - 10% of 1499.85 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
26.23 × 31.82 + 44.8% of 1200 + ? = 1520
66.05 × 17.95 – 38.99 × 18.12 = (60 + ?) × 6
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, find the value of (4A - B) .
Relevant for Exams:
