Question
Train P travelling at 58 km/hr crosses another train Q,
having three fourth of its length and travelling in opposite direction at 32 km/hr in 14 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.Solution
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (58 + 32) x 5/18 = {x + (3x/4)}/14 ⇒ 90 x 5/18 = (7x/4)/14 ⇒ x = 200 m Therefore, let the length of the platform be y metre ⇒ 58 x 5/18 = (200 + y)/36 ⇒ 580 = 200 + y ⇒ y = 580 – 200 = 380 m
13.5% of (100 + ?) = 27
15% of 1800 + 22 = ?Â
`sqrt(7744)` Â Â -Â `sqrt(4761)` +Â `sqrt(8281)` Â +Â `sqrt(5625)` + ? = 1856Â
15% of 360 × 20% of ? = 324
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
1672 ÷ 19 = ?% of 220
[192 ÷ 6 × 5] ÷ (? + 3) = 20Â
- What will come in place of the question mark (?) in the following questions?
144÷12+18×2=? 140% of 1270 + 60% of 2085 = 1881 + ‘?’% of 287