A 160 m long train crosses another 290 m long train
running in the opposite direction in 10 seconds. If the shorter train crosses a pole in 8 seconds, what is the speed of longer train?
A108 km/hrCorrect AnswerIncorrect Answer
B90 km/hrCorrect AnswerIncorrect Answer
C72 km/hrCorrect AnswerIncorrect Answer
D60 km/hrCorrect AnswerIncorrect Answer
Solution
Speed of the shorter train = 160/8 = 20 m/sec Let the speed of the longer train be x km/hr According to the question, ⇒ (20 + x) = (160 + 290)/10 ⇒ 20 + x = 450/10 ⇒ x = 45 – 20 = 25 ⇒ x = 25 x 18/5 = 90 km/hr