Question
A train has to cover a distance of 210 km in 14 hours.
If it covers half journey in 4/7th time, then the speed of covering the remaining distance in the time left has to be:Solution
Speed = Distance/time = 210/14 = 15 km/hr According to the question, New time = 4/7 x 14 = 8 hrs New distance = 1/2 x 210 = 105 km Required speed = Distance left/Time left = 105/6 = 17.5 km/hr
Statements: X ≥ Y= Z ≤ A, K < A ≤ M < W
Conclusion:
I. M = Y
II. M > Y
III. K ≤ Y
Statements: Y $ Z, H $ D, Z * D
Conclusions: a) Y & H b) Y * D
...Which of the following letters should be placed in the blank spaces respectively (in the same order from left to right) to complete the given expression...
Statements: X @ Y $ Z & U, Z @ V
Conclusions: I. V # X II. V $ X
...In the following question, a relationship between different elements is shown in the statements, followed by two conclusions I and II. Assuming the stat...
Statements: S ≥ U < N = A; D > U ≥ C
Conclusions: I. A > D II. C < A
Statement: C > B > T < J > D > M < Z
Conclusion: I. C > M II. C > Z
Statements: P < Q ≤ R ≤ S; P > T = V ≥ X; S ≤ W = Y < U
Conclusions:
I. U > R
II. W > X
III. Q < Y
Statement: M > N ≥ O; M ≤ P = Q; R > N
Conclusion: I. N < Q II. R > M
Statement:
J < K ≤ M > O; M > P < Z; Z = R
Conclusion:
I. P < K
II. R > K
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