Question
A and B alone can complete a work in 20 and 80 days,
respectively. 50% of the work is completed by C in 5x days, and the remaining work is completed by A and B working together in ‘x’ days. Find the time taken by B and C to complete the whole work while working together.Solution
Time taken by A and B to complete the whole work while working together = (20 × 80)/(20 + 80) = 16 days So, x = 16/2 = 8 (Since, 50% of the work is done by A and B together) As, time taken by C to complete 50% of the work = 8 × 5 = 40 days So, time taken by C to complete the entire work = 40 × 2 = 80 days Therefore, time taken by B and C to complete the whole work while working together = (80 × 80)/(80 + 80) = 40 days
The minimum value of 25 sin2 θ + 16 cos2 θ is
- If 2cosec 2 A – cot 2 A = 5 and 0 o < A < 90 o , then find the value of ‘A’.
- If sec 2P = sin² 60⁰ + sec 60⁰ - cos² 30⁰, then determine the value of (√3tan P + cot² P)
(tan 5x - tan 3x - tan 2x) = ?
If cot8A = tan(A+8˚), find the value of A? Given that 8A and A+8 are acute angles.
If (3cos A - sin A) = 2 cos (90° - A), then find the value of cot A.
Two points P and Q are at the distance of x and y (where y > x) respectively from the base of a building and on a straight line. If the angles of elevat...
If sec x + tan x = 11 then find secx?