Question
A, B, and C together can complete a task in 8 days. A
alone can do it in 24 days, and B alone can do it in 18 days. How long will it take C alone to finish the work?Solution
Work done by A, B, and C together in one day = 1/8 Work done by A in one day = 1/24 Work done by B in one day = 1/18 Work done by C in one day = (1/8) - (1/24 + 1/18) LCM of 8, 24, and 18 = 72 Work done by C in one day = (9/72) - (3/72 + 4/72) = 9/72 - 7/72 = 2/72 Time taken by C = 1 ÷ (2/72) = 36 days Correct Option: d
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
The average of 5 positive integers was initially computed as 30. However, it was discovered later that an error had occurred duri...
Raju invests Rs. (p + 200) at a simple interest rate of 25% per annum for a period of 6 years and earns a total interest of Rs. (...
(44.11/4.01) + (11.99/3.03) + 23.9% of 49.978 = ?3.03
24.98% of 1682 × (18.2659 ÷ 9.04965)(–4) = ?Â
At a village trade fair a man buys a horse and a camel together for Rs 51,250. He sold the horse at a profit of 25 % and the camel at a loss of 20 %. If...
What approximate value should replace the question mark?
(599.90 ÷ 12.02) + (179.98 ÷ 6.00) = ?% of 200.0 - 20.3
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
- √143.88 X 31.87 + √323.99 X 15.99 - 31.99 X √195 = ?