Question
A, B, and C can individually complete a task in 20
days, 15 days, and 10 days, respectively. B and C begin the task and work together for 3 days, after which both of them leave. How many days will it take for A to finish the remaining work by themselves?Solution
Let the total work be 60 units (L.C.M of 20, 15 and 10) Efficiency of A = 60/20 = 3 units/day Efficiency of B = 60/15 = 4 units/day Efficiency of C = 60/10 = 6 units/day Amount of work completed by B and C in 3 days = (6 + 4) × 3 = 30 units Time taken by A to complete the remaining work alone = (60 – 30)/3 = 10 days
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