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Start learning 50% faster. Sign in nowLet the total work be 60 units (L.C.M of 20, 15 and 10) Efficiency of A = 60/20 = 3 units/day Efficiency of B = 60/15 = 4 units/day Efficiency of C = 60/10 = 6 units/day Amount of work completed by B and C in 3 days = (6 + 4) × 3 = 30 units Time taken by A to complete the remaining work alone = (60 – 30)/3 = 10 days
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