Question
‘D’ and ‘E’ together can finish a task in 40
days, while ‘E’ and ‘F’ together can finish the same task in 30 days. ‘D’ and ‘E’ together worked on it for 35 days and then ‘F’ alone completed the remaining work in 10 days. If ‘D’, ‘E’, and ‘F’ started a certain task and worked together till its completion for which they received Rs. 1800 as total wage, then the share of ‘D’ out of the total wage will be:Solution
Let the total amount of work = LCM of 40 and 30 = 120 units Work done by ‘D’ and ‘E’ in one day = 120/40 = 3 units Work done by ‘E’ and ‘F’ in one day = 120/30 = 4 units Work done by ‘D’ and ‘E’ in 35 days = 35 × 3 = 105 units Remaining work = 120 - 105 = 15 units Efficiency of ‘F’ = 15/10 = 1.5 units per day Efficiency of ‘E’ = 4 - 1.5 = 2.5 units per day Efficiency of ‘D’ = 3 – 2.5 = 0.5 units per day Share of ‘D’ = (0.5 / (0.5 + 2.5 + 1.5)) × 1800 = Rs 200
51, 60, 78, ?, 141, 186
14, 20, 29, 44, 65, ?
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
Find the missing number, in the given number series.
6, 12, 36, ?, 720, 4320
What will come in place of the question mark (?) in the following series?
2, 5, 10, 17, 26, ?, 5094 115 138 163 190 ?
What will come in place of the question mark (?) in the following series?
206, 187, ?, 157, 146, 139
38, 41, 50, ?, 158, 401
63 131 267 ? 1083 2171
5 6 15 40 89 170 ?
...
