Question
Pipe βAβ and pipe βBβ, together can fill 40% of
a tank in 6 hours while pipe βCβ takes 35 hours to empty it. Pipe βAβ and pipe βBβ were opened together. After 12 hours, pipe βCβ is also opened. Find the total time taken to fill the empty tank this way.Solution
Time taken by pipe βAβ and pipe βBβ, together to fill the tank = 6/0.40 = 15 hours Let the total capacity of tank = 105units (LCM of 15 and 35) Efficiency of pipe (A + B) = 105/15 = 7 units/hour Efficiency of pipe βCβ = 105/35 = 3 units/hour Tank filled by pipe (A + B) in 28 hours = 12 Γ 7 = 84 units Time taken by all three pipes to fill the remaining tank = (105 β 84)/ (7 β 3) = 21/4 hrs. =.5.25hours Total time taken = 12 + 5.25 = 17.25 hours
Simplify:
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