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    Question

    Pipe ‘A’ and pipe ‘B’ can fill a cistern in 20

    minutes and 15 minutes respectively. Pipe ‘C’ alone can empty the cistern in 10 minutes. If all three pipes are opened together then what is the time taken to fill 25% of the cistern? ty-ssc
    A 24minute Correct Answer Incorrect Answer
    B 15minute Correct Answer Incorrect Answer
    C 18minute Correct Answer Incorrect Answer
    D 12minute Correct Answer Incorrect Answer

    Solution

    Let the capacity of the cistern = 60 units Then, efficiency of pipe ‘A’ = 60/20 = 3 units/minute Efficiency of pipe ‘B’ = 60/15 = 4 units/minute Efficiency of pipe ‘C’ = 60/10 = 6 units/minute So, combined efficiency of pipes ‘A’, ‘B’ and ‘C’ = 3 + 4 – 6 = 1 units/minute 25% of the cistern’s capacity = 15 units Therefore, time taken by all 3 pipes together to fill 25% of the cistern = 15/1 = 15 minutes

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