Time taken by B to complete the work = 25 – 5 = 20 days Let the total work = 100 units Efficiency of A = 100/25 = 4 units/day Efficiency of B = 100/20 = 5 units/day Required time taken = 0.90 x 100/(4+5) = 10 days
(?)2 + 3.113 = 22.92 – 61.03
(5.89 × 4.76) + (3.65 × 14.89) = ? × 5.76
A can complete a piece of work in 15 days. B is 30% more efficient than A. If they work together, how many days will it take to complete the work?
(34.03 + 101.98) ÷ 17.211 = 89.9 – 25.23% of ?
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65
3.98 × 29.67 ÷ 11.90 of √24.89 = ?% of 199.79
(80.95) (1/4) + (3.05) 3 - 119.78 × 2.15 + (14.98)2 = ?
(2099.92 ÷ 25.02 of ? × 199.56 + 1199.95) = 3999.86
`sqrt(1297)` + 189.99 =?
