Question
βAβ alone can complete a work in 30 days. βBβ
alone can complete the same work in 40 days. If βAβ and βBβ work together for 6 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 120 units {LCM of 30 and 40} Then, efficiency of βAβ = 120/30 = 4 units/day Efficiency of βBβ = 120/40 = 3 units/day Combined efficiency of βAβ and βBβ = 4 + 3 = 7 units/day Work completed by βAβ and βBβ together in 6 days = 7 Γ 6 = 42 units Remaining work = 120 β 42 = 78 units Time taken by βAβ alone to complete the remaining work = 78/4 = 19.5 days
14.99% of 7820 + 5535.25 Γ· 123.001 - ? = 84
18.22 Γ 11.99 + 154.15 = ?
Β (3/5) of 3025 + (18Β² + 12Β²) = ? + 22.22% of 1125
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?
? = 16.08 + 13.99 Γ 25.07
20.99Β ΓΒ β4.09Β Γ 30.09 = ? Γ β195.99 Γ 15.09
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
30.01 Γ β1023 + 196 = ? 2 β 287
?% of (150.31 Γ· 14.97 Γ 50.011) = 319.98