Question
‘A’ alone can complete a work in 60 hours. ‘A’
started the work alone and left after working on it for 40 hours. If ‘B’ completed the rest of the work in 20 hours then find the time taken by ‘A’ and ‘B’ together to complete the whole work.Solution
Let the total work = 300 units Then, efficiency of ‘A’ = (300/60) = 5 units/hour Work completed by ‘A’ alone in 40 hours = 5 × 40 = 200 units Remaining work = 300 – 200 = 100 units So, efficiency of ‘B’ = 100/20 = 5 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 5 + 5 = 10 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (300/10) = 30 hours
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