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Time taken by Nikhil to complete the whole work alone = 14/0.40 = 35 days Let the total work = 35 units Efficiency of (Akhil + Nikhil) = 35/7 = 5 units/day Efficiency of Nikhil = 35/35 = 1 units/day Efficiency of Akhil = 5 - 1 = 4 units/day Therefore efficiency of Sachin = 1.25 x 4 = 5 units/day Time taken by Sachin to complete the whole work alone = 35/5 = 7 days
Statements:
A ≥ T > I, D > I, U = P ≥ I
Conclusions:
I. U > D
II. A > I
Statements:
A < B ≤ T < Y = O; V < R > K ≥ F > O
Conclusions:
I). B < R
II). Y ≥ K
... In these questions, relationship between different elements is shown in the statements. The statements are followed by conclusions.
Statements:
M < K ≤ G ≤ Z; P = J > Z; I ≥ R > P;
Conclusions:
I. K ≤ P
II. M < R
Statement: X > P ≥ W < Z ≤ T < S, P ≥ V
I. P > T
II. X > V
Statements: K * D, D $ N, N % M, M © W
Statements: J > A > G < N < K = V
Conclusion
I. J > K
II. V > A
...Statements: I ≤ Z < V; Z ≤ P < A; X < I ≥ W
Conclusions:
I. A > I
II. W ≤ P
III. X < V
Statements: I < Q = S = T ≤ U ≤ W < X > Y = V
Conclusions:
I. I > Y
II. W ≥ Q
III. T < V
...