Question
Akhil and Nikhil together can complete a work in 7 days
while Nikhil alone takes 14 days to complete 40% of the work. If the efficiency of Sachin is 25% more than that of Akhil, then find the time taken by Sachin alone to complete the whole work.Solution
Time taken by Nikhil to complete the whole work alone = 14/0.40 = 35 days Let the total work = 35 units Efficiency of (Akhil + Nikhil) = 35/7 = 5 units/day Efficiency of Nikhil = 35/35 = 1 units/day Efficiency of Akhil = 5 - 1 = 4 units/day Therefore efficiency of Sachin = 1.25 x 4 = 5 units/day Time taken by Sachin to complete the whole work alone = 35/5 = 7 days
√ (12+√ (12+√ (12+ ⋯ ∞ ))Â
What will come in the place of question mark (?) in the given expression?
?% of 740 – 8% of 650 = 7.2
Find the simplified value of the given expression:
(12 ÷ 3 of 2 + 11 of 2) ÷ 4
What will come in the place of question mark (?) in the given expression?
75% of (√64 × 8 - 16) × ? = 15²
`(sqrt(1296)xx42)/(120+200)` = ?
3/7 of 504 ÷ 12 + 17 = √?
Simplify the expression:
(9x² - 25) / (3x + 5)
Simplify the following expressions and choose the correct option.
45% of 640 + (2/5 of 350) = ?
120% of 25 + 80 X 2 = ?2 - 6
