Question
A, B, and C together can do a work alone in 14 days, 56
days, and 70 days respectively. A alone starts the work and work for 3 days and leaves the work, then B alone does the work for 8 days and leaves the work. If remaining work is done by C alone then for how many days has C worked?Solution
Total work = LCM of 15, 45 and 90 = 90 units Unit per day of A = 90/15 = 6 Unit per day of B = 90/45 = 2 Unit per day of C = 90/90 = 1 Units of work done by A in 3 days = 6 × 3 = 18 units Units of work done by B in 8 days = 8 × 2 = 16 units Remaining work = 90 – (18 + 16) = 56 units So, C has worked for 56/1 = 56 days
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