Question
A alone can complete 50% of a work in 15 days while B
takes 10 days more than A to complete it. If B and C together can complete the work in 20 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 15/0.5 = 30 days Time taken by B alone to complete the entire work = 30 + 10 = 40 days Let the total work = L.C.M of 30, 40 and 20 = 120 units Then, efficiency of B = (120/40) = 3 units/day Combined efficiency of B and C = (120/20) = 6 units/day So, efficiency of C alone = 6 – 3 = 3 units/day So, time taken by C alone to complete the entire work = (120/3) = 40 days
√323.89 × (3.20) ÷ 9.02 =?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
23.98% of 624.99 = 19.98% of ? + 14.98% of 639.99
Direction: Please solve the following expression and choose the closest option
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
12, 16, ?, 36, 52, 72
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(6859.01)1/3 × 10.11 × 14.47 ÷ 20.32 = ? + 45.022
33.33% of 809.891 + 66.66% of 212.91 = ?
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