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Let, total amount of work = 360 units (LCM of 40, 45 and 36) Efficiency of ‘A’ = 360/40 = 9 units/day Efficiency of ‘B’ = 360/45 = 8 units/day Efficiency of ‘C’ = 360/36 = 10 units/day Let, the whole work is completed in ‘x’ days So, ‘A’ worked for ‘x – 20’ days And, ‘C’ worked for x – 20 + 8 = ‘x – 12’ days So, 9(x – 20) + 10(x – 12) + 8 × x = 360 => 27x = 660 => x = 24.44 ≈ 24 days
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