Question
A carriage travels in the fog passed along a man who
was walking @ 3kmph in the same direction. He could see the carriage for 4 minutes and it was visible to him upto a distance of 100 metres. What was the speed of carriage?Solution
60 min = 3,000 4 min = 3000/60 × 4 ⇒ 200 Carriage ⇒ 4 min = 300 60 min = 300/4 × 60 ⇒ 4500 Speed = 4.5kmph Alternate Method: (d₁)/(d₂) = (S₁)/(S₂) 300/200 = (S₁)/3 ⇒ S₁ ⇒ 9/2 = 4.5kmph
The value of ((0.27)2-(0.13)2) / (0.27 + 0.13) is:
4.56 + 56.4 + 64.5 = ? + 10.46
(3/7) x 868 + 25% of 240 = (? + 65)
(506 ÷ 22 + 9 × 3) × ? = 900 ÷ 9
(72 + 30) ÷ 6 + [{75 ÷ 25) + 6} × 2] = ?
(560 ÷ 32) × (720 ÷ 48) = ?
√729 × 5 + 270 - 3 ÷ ∛27 + 4 × ? = 484
(392 + 427 + 226 – 325) ÷ (441 + 128 – 425) = ?
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
‘A’ and ‘B’ invested Rs. 5000 and Rs. 4200, respectively in a business, together. After 7 months, ‘A’ withdrew 25% of his initial investment...