Question
Distance between two stations is 1120 km. Train βAβ
takes 6 hours more than train βBβ to cover this distance. If speed of train βBβ is 60 km/h more than speed of train βAβ, then find the time taken by train βBβ to cover the distance.Solution
Let speed of train βAβ is βxβ km/h So, speed of train βBβ = βx + 60β km/h Let time taken by train βAβ to cover the whole distance is βt + 6β hours So, time taken by train βBβ to cover the whole distance = βtβ hours So, x(t + 6) = (x + 60) Γ t Or, 6x = 60t Or, x = 10t And, x(t + 6) = 1120 Or, 10t(t + 6) = 1120 Or, tΒ² + 6t β 112 = 0 Or, tΒ² + 14t β 8t β 112 = 0 Or, t(t + 14) β 8(t + 14) = 0 Or, (t + 14)(t β 8) = 0 Or, t = 8 So, time taken by train βBβ = 8 hours
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