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ATQ,
Let the usual speed of the driver be '2s' km/h and the distance be 'd' km.
Let the usual time taken be 't' hours.
ATQ;
(d/2s) = t
Or, d = 2ts ........ (I)
Now, if he travels at half his speed:
(d/s) = t + (45/60)
Using equation (I), we have;
(2ts/s) = t + (3/4)
Or, 2t = t + (3/4)
Or, t = (3/4)
Therefore, the usual time taken by the driver to reach his destination = (3/4) hours or 45 minutes.
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