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    Question

    A driver moving at half of his normal speed takes 45

    minutes more than the typical time to reach his destination. Determine the typical time taken by him.
    A 19 min Correct Answer Incorrect Answer
    B 12 min Correct Answer Incorrect Answer
    C 45 min Correct Answer Incorrect Answer
    D 27 min Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the usual speed of the driver be '2s' km/h and the distance be 'd' km.

    Let the usual time taken be 't' hours.

    ATQ;

    (d/2s) = t

    Or, d = 2ts ........ (I)

    Now, if he travels at half his speed:

    (d/s) = t + (45/60)

    Using equation (I), we have;

    (2ts/s) = t + (3/4)

    Or, 2t = t + (3/4)

    Or, t = (3/4)

    Therefore, the usual time taken by the driver to reach his destination = (3/4) hours or 45 minutes.

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