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      Question

      A driver moving at half of his normal speed takes 45

      minutes more than the typical time to reach his destination. Determine the typical time taken by him.
      A 19 min Correct Answer Incorrect Answer
      B 12 min Correct Answer Incorrect Answer
      C 45 min Correct Answer Incorrect Answer
      D 27 min Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the usual speed of the driver be '2s' km/h and the distance be 'd' km.

      Let the usual time taken be 't' hours.

      ATQ;

      (d/2s) = t

      Or, d = 2ts ........ (I)

      Now, if he travels at half his speed:

      (d/s) = t + (45/60)

      Using equation (I), we have;

      (2ts/s) = t + (3/4)

      Or, 2t = t + (3/4)

      Or, t = (3/4)

      Therefore, the usual time taken by the driver to reach his destination = (3/4) hours or 45 minutes.

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