Question
In a 1,200-meter race between 'A' and 'B', 'A' gives 'B' a
head start of 48 meters. Both 'A' and 'B' finish the race simultaneously. If 'B's speed is 6 m/s, what is the speed of 'A'?Solution
Distance covered by 'A' = 1,200 metres
Distance covered by 'B' = 1200 - 48 = 1,152 metres
Since, both 'A' and 'B' takes same time to finish the race.
So, the time is constant, which means,
Speed ∝ Distance
So, the ratio of speed of 'A' to that of 'B' = (Distance covered by 'A') :(Distance covered by 'B') = 1200:1152 = 25:24
So, the speed of 'A' = (25/24) X 6 = 6.25 m/s
Find the difference between minimum and maximum value of 'c' such that '5c4632' is always divisible by 3.
Five numbers are arranged in decreasing order. The average of the first four numbers is 60, and the average of the last four numbers is 55. What is the ...
In a two-digit positive number, the digit in the tens place is one less than the square of the digit in the units place. Additionally, the difference be...
- Which of the following is not a perfect square?
Find the sum of all the numbers between 2500 and 9800, which are divisible by 20, 28 and 35.
- When is the expression 16x - 4x² - 48 greater than zero?
'N' is the largest three-digit number which leaves 5 as a remainder when divided by 6, 9, and 15. What is the smallest number that needs to be added to ...
When N is divisible by 5 the remainder is 2. What is the remainder, when n³ is divided by 5?
What must be added to (7/20) to make it (3/4)?
The product of two positive values is 81 times the product of the first value and the reciprocal of the second value. A third value is 50% more than the...
Relevant for Exams:
