Question
In a 1,200-meter race between 'A' and 'B', 'A' gives 'B' a
head start of 48 meters. Both 'A' and 'B' finish the race simultaneously. If 'B's speed is 6 m/s, what is the speed of 'A'?Solution
Distance covered by 'A' = 1,200 metres
Distance covered by 'B' = 1200 - 48 = 1,152 metres
Since, both 'A' and 'B' takes same time to finish the race.
So, the time is constant, which means,
Speed ∝ Distance
So, the ratio of speed of 'A' to that of 'B' = (Distance covered by 'A') :(Distance covered by 'B') = 1200:1152 = 25:24
So, the speed of 'A' = (25/24) X 6 = 6.25 m/s
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